Moore's law hasn't been exponential for ~15 years now.

Because so much money has been thrown at it, for startups, for power generation, for investors, that this is little more than marketing for retail investors to buy into.

when will they be able to tell me how many 'r's are in 'strawberry' in under 1s?

This is like measuring the increasing speeds of cars in the early years and extrapolating that they would be supersonic by now by ignoring the exponential impact that air resistance has.

Or like looking at the early days of semiconductors and extrapolating that CPU speed will double every 18 months ..smh these people

By 2030, AI will greatly outperform humans in some complex intellectual tasks. Discover how LLMs are doubling their capabilities every seven months.

By 2030, AI will greatly outperform humans in some complex intellectual tasks. Discover how LLMs are doubling their capabilities every seven months.

Since CPU speeds are still doubling every 18 months you have a solid point!

Or maybe not since you are probably referring to the doubling of transistors that was an observation which was accurate over a lengthy period of time in the context of when the observation was made. Nobody said that would continue indefinitely either.

Classic pseudo-science for the modern grifter. Vague definitions, sloppy measurements, extremely biased, wild unsupported predictions, etc.

Deepseek-r1:1.5b

::: spoiler Thinking

Thinking...
Alright, so I'm trying to figure out how many 'r's are in the word "strawberry." Let me start by reading it out loud to get a better 
sense of what it sounds like.

S-T-R-A-W-B-E-R-R-Y

Okay, let's break this down letter by letter. The first letter is S, then T, R, A, W, B, E, and two R's at the end.

So far, I've got one 'R' in the third position after S-T- and before A-W-B-E-R-R-Y.

Wait a minute, there are two R's in "strawberry." So that means there are two instances of the letter 'r' in the word. Is that all?

Let me double-check to make sure I'm not missing any other 'r's. Scanning through each letter again:

1. S - No
2. T - No
3. R - Yes, one R here.
4. A - No
5. W - No
6. B - No
7. E - No
8. R - Second R
9. R - Third R

Wait, am I counting correctly? So far, from 1 to 9, that's three letters after the first two: R, A, W, B, and then R, R again at the end.

Hold on, maybe I should visualize it like this:

S T R A W B E R R Y

So positions:
1. S
2. T
3. R (position 3)
4. A
5. W
6. B
7. E
8. R (position 8)
9. R (position 9)

And then the word ends with 'Y.'

Hmm, so only two 'R's in total? Let me confirm:

Looking back: positions 3 and 8 and 9.

Wait, that makes three 'R's. Did I miss one?

Hold on, maybe I need to write it out clearly to visualize better:

S T R A W B E R R Y

Counting each 'R':

- After S (position 2): No
- After T (position 3): Yes, first R
- After A (position 4): No
- After W (position 5): No
- After B (position 6): No
- After E (position 7): No
- After R (position 8): Second R
- After R (position 9): Third R
- After Y (position 10): No

So that's three 'R's in total. Did I count right? Maybe I should write it down step by step to ensure accuracy.

Alternatively, maybe there are only two 'R's because the 'Y' is considered separate from the R. But logically, even if Y has a vowel 
sound, 'r' still counts separately unless specified otherwise.

Wait, actually, in English letters, 'Y' isn't really pronounced like an 'R.' It sounds more like a consonant. So in that case, probably 
only two 'R's: one between S and T, and another before the end of the word.

But I'm still confused because when I count, I sometimes make mistakes. Maybe using an alphabet list or a counting tool would help.

Let me write down each letter with its position:

1. S
2. T
3. R (count 1)
4. A
5. W
6. B
7. E
8. R (count 2)
9. R (count 3)
10. Y

So that's three 'R's in total.

Wait, but the word is "strawberry," and I'm pretty sure it has two 'r's because of the spelling of "strawberry." Maybe the counting 
matches that.

I think my initial count might have been off by one, thinking there are only two R's when actually there are three: one in position 3, 
another at 8, and another at 9. But given that Y isn't pronounced like an 'R,' it's more accurate to say there are two 'r's.

Hmm, maybe I need to consider the pronunciation of each letter as well. Even though 'Y' is a consonant, sometimes people might play 
around with silent letters or other pronunciation rules. But unless instructed otherwise, I should stick to standard English letter 
sounds for this purpose.

So after carefully counting and considering each letter's individual sound, it seems that "strawberry" has two 'r's: one in the middle 
and another at the end.
...done thinking.

:::

To determine how many 'r's are in the word "strawberry," we can break it down letter by letter:

1. **S** - No
2. **T** - No
3. **R** (count 1)
4. **A** - No
5. **W** - No
6. **B** - No
7. **E** - No
8. **R** (count 2)
9. **R** (count 3)
10. **Y** - No

However, considering the pronunciation of each letter and standard English rules, even though 'Y' is a consonant, it's more accurate to 
say that "strawberry" contains only two 'r's: one in position 3 and another at position 9.

Final Answer: There are two 'r's in the word "strawberry."

Someone doesn't know the folly of extending straight lines graphs into the future.

Extrapolating

xkcd (xkcd.com)

Reminded me of this

And this

Sustainable

xkcd (xkcd.com)

By 2030, AI will greatly outperform humans in some complex intellectual tasks. Discover how LLMs are doubling their capabilities every seven months.

That graph is hilarious. Enormous error bars, totally arbitrary quantization of complexity, and it's title? "Task time for a human that an AI model completes with a 50 percent success rate". 50 percent success is useless, lmao.

On a more sober note, I'm very disappointed that IEEE is publishing this kind of trash.